X^2+6x=79

Solution for X^2+6x=79 equation:

X^2+6X=79

We move all terms to the left:

X^2+6X-(79)=0

a = 1; b = 6; c = -79;
Δ = b2-4ac
Δ = 62-4·1·(-79)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{22}}{2*1}=\frac{-6-4\sqrt{22}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{22}}{2*1}=\frac{-6+4\sqrt{22}}{2}
$